(2/c+2)+(5/c^2-4)

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Solution for (2/c+2)+(5/c^2-4) equation: 


D( c )

c^2 = 0

c = 0

c^2 = 0

c^2 = 0

1*c^2 = 0 // : 1

c^2 = 0

c = 0

c = 0

c = 0

c in (-oo:0) U (0:+oo)

2/c+5/(c^2)-4+2 = 0

2*c^-1+5*c^-2-2 = 0

t_1 = c^-1

5*t_1^2+2*t_1^1-2 = 0

5*t_1^2+2*t_1-2 = 0

DELTA = 2^2-(-2*4*5)

DELTA = 44

DELTA > 0

t_1 = (44^(1/2)-2)/(2*5) or t_1 = (-44^(1/2)-2)/(2*5)

t_1 = (2*11^(1/2)-2)/10 or t_1 = (-2*11^(1/2)-2)/10

t_1 = (-2*11^(1/2)-2)/10

c^-1-((-2*11^(1/2)-2)/10) = 0

1*c^-1 = (-2*11^(1/2)-2)/10 // : 1

c^-1 = (-2*11^(1/2)-2)/10

-1 < 0

1/(c^1) = (-2*11^(1/2)-2)/10 // * c^1

1 = ((-2*11^(1/2)-2)/10)*c^1 // : (-2*11^(1/2)-2)/10

10*(-2*11^(1/2)-2)^-1 = c^1

c = 10*(-2*11^(1/2)-2)^-1

t_1 = (2*11^(1/2)-2)/10

c^-1-((2*11^(1/2)-2)/10) = 0

1*c^-1 = (2*11^(1/2)-2)/10 // : 1

c^-1 = (2*11^(1/2)-2)/10

-1 < 0

1/(c^1) = (2*11^(1/2)-2)/10 // * c^1

1 = ((2*11^(1/2)-2)/10)*c^1 // : (2*11^(1/2)-2)/10

10*(2*11^(1/2)-2)^-1 = c^1

c = 10*(2*11^(1/2)-2)^-1

c in { 10*(-2*11^(1/2)-2)^-1, 10*(2*11^(1/2)-2)^-1 }

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